-4[x+3(x-5)]=3(3x+20)

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Solution for -4[x+3(x-5)]=3(3x+20) equation:


Simplifying
-4[x + 3(x + -5)] = 3(3x + 20)

Reorder the terms:
-4[x + 3(-5 + x)] = 3(3x + 20)
-4[x + (-5 * 3 + x * 3)] = 3(3x + 20)
-4[x + (-15 + 3x)] = 3(3x + 20)

Reorder the terms:
-4[-15 + x + 3x] = 3(3x + 20)

Combine like terms: x + 3x = 4x
-4[-15 + 4x] = 3(3x + 20)
[-15 * -4 + 4x * -4] = 3(3x + 20)
[60 + -16x] = 3(3x + 20)

Reorder the terms:
60 + -16x = 3(20 + 3x)
60 + -16x = (20 * 3 + 3x * 3)
60 + -16x = (60 + 9x)

Add '-60' to each side of the equation.
60 + -60 + -16x = 60 + -60 + 9x

Combine like terms: 60 + -60 = 0
0 + -16x = 60 + -60 + 9x
-16x = 60 + -60 + 9x

Combine like terms: 60 + -60 = 0
-16x = 0 + 9x
-16x = 9x

Solving
-16x = 9x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9x' to each side of the equation.
-16x + -9x = 9x + -9x

Combine like terms: -16x + -9x = -25x
-25x = 9x + -9x

Combine like terms: 9x + -9x = 0
-25x = 0

Divide each side by '-25'.
x = 0

Simplifying
x = 0

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